How is the above transformation best carried out?

O s O_{4} : N a H S O_{3}

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H_{2} S O_{4} / H_{2} O

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H g S O_{4} / H_{2} S O_{4}

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H I O_{4}

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Solution

The correct option is C $H g S O_{4} / H_{2} S O_{4}$
$\begin{matrix} {On addition of HgSO}_{4} / H_{2} {SO}_{4} with alkyne adds OH to most hindered carbon and H to least hindered Carbon i.e addition of water. \end{matrix}$

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