How is work done by a force measured when the force:
$(i)$ is in the direction of displacement.
$(i i)$ is at an angle to the direction of displacement.

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Solution

$(i)$ Work done by a force when the force is in the direction of displacement
$=$ Force $\times$ Displacement of the point of application of the force in the direction of force.
$(i i)$ Work done by a force when the force is at an angle $(θ)$ to the direction of displacement $=$ Force $\times$ component of displacement in the direction of force.
$=$ Force $\times d cos θ$
[ $d$ is the displacement of the body at the angle $θ$ to the direction of force]

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A body, when acted upon by a force of 10 kgf, gets displaced by 0.5 m. Calculate the work done by the force, when the displacement is (i) in the direction of force, (ii) at an angle of $60^{o}$ with the force, and (iii) normal to the force.(g=10 N $k g^{- 1}$ ).

A force F acts on a body and displaces it by a distance S in a direction at an angle $θ$ with the direction of force.

(a) Write the expression for the work done by the force.

(b) What should be the angle between the force and displacement to get (i) zero, (ii) maximum, work?

Q. A force of

10 N

displaces an object by

10 m

. If work done is

50 J

, then direction of force makes an angle with direction of displacement

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How is work done by a force measured when the force:(i) is in the direction of displacement.(ii) is at an angle to the direction of displacement.

How is work done by a force measured when the force:
$(i)$ is in the direction of displacement.
$(i i)$ is at an angle to the direction of displacement.