How long does it take, in seconds, for a 160 m long train to enter a tunnel when the train is travelling at 170 km/h?

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Solution

$T i m e =$ $\frac{Distance}{s p e e d}$

speed should be converted to m/s so multiplying by $\frac{1000}{3600} = \frac{5}{18}$

$∴ 170 \times \frac{5}{18} = 47.22$ m/s

$∴$ time = $\frac{160}{47.22} = 3.888$ s

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How long does it take, in seconds, for a 160 m long train to enter a tunnel when the train is travelling at 170 km/h?

Time= Distance speed speed should be converted to m/s so multiplying by 10003600=518 ∴170×518=47.22 m/s ∴ time = 16047.22=3.888 s

$T i m e =$ $\frac{Distance}{s p e e d}$

speed should be converted to m/s so multiplying by $\frac{1000}{3600} = \frac{5}{18}$

$∴ 170 \times \frac{5}{18} = 47.22$ m/s

$∴$ time = $\frac{160}{47.22} = 3.888$ s