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Faraday's Second Law

How long will...

Question

How long will it take for a uniform current of 6.0 ampere to deposit 78.0 g gold from a solution of $A u C l_{4}^{-}$ ?

A

230.6min.

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B

321.2 min.

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C

318.4 min.

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D

2111.8 min.

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Solution

The correct option is C 318.4 min.
Charge required for plating out $78$ g of Gold = $\frac{3 \times 96500 \times 78}{197} = 114624.36$

$Q = I \times t$

$t = \frac{114624.3655}{6} \approx 19104 s e c = 318.4 m i n$

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