How many $1 c m^{3}$ are there in $1 m^{3}$ ?

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Solution

$1 c m^{3} = (1 c m)^{3} = (1 \times 10^{- 2} m)^{3} = 10^{- 6} m^{3}$

So by $\frac{1 m^{3}}{1 c m^{3}} = \frac{1 m^{3}}{10^{- 6} m^{3}} = 10^{6}$

So $10^{6} c m^{3}$ fits in $1 m^{3}$

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How many 1 cm3 are there in 1 m3?

1cm3=(1cm)3=(1×10−2m)3=10−6m3So by 1m31cm3=1m310−6m3=106So 106cm3 fits in 1m3

How many $1 c m^{3}$ are there in $1 m^{3}$ ?

$1 c m^{3} = (1 c m)^{3} = (1 \times 10^{- 2} m)^{3} = 10^{- 6} m^{3}$

So by $\frac{1 m^{3}}{1 c m^{3}} = \frac{1 m^{3}}{10^{- 6} m^{3}} = 10^{6}$

So $10^{6} c m^{3}$ fits in $1 m^{3}$