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Question

How many 176 Ω resistors (in parallel) are required to carry 5A on a 220V line?

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Solution

Step 1 : Equivalent resistance
Let n be the number of resistors to be connected in parallel
Then, R1=R2=......=Rn=R=176 Ω
Now, 1Req=1R1+1R2+.....1Rn
1Req=nR1=n176
Req=176/n ....(1)

Step 2 : Applying Ohm's law
V=IReq
220=5Req
220=5×176/n (Using Equation (1))
n=4

Hence, four resistors are required.

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