Question

How many 176 W resistors (in parallel) are required to carry 5 A in 220 V line?

Answer 1

Here, I = 5A, V = 220 V.

Resistance required in the circuit, R = $\frac{V}{I}$ = $\frac{220V}{5A}$ = 44 W, Resistance of each resistor, r = 176 W

If n resistors, each of resistance r, are connected in parallel to get the required resistance R, then R = $\frac{r}{n}$ or n = $\frac{r}{R}$ = $\frac{176}{44}$ = 4