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Byju's Answer
Standard XII
Mathematics
Permutation under Restriction
How many 2 ...
Question
How many
2
- digit positive integers are divisible by
4
or
9
?
A
32
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B
22
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C
30
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D
34
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E
10
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F
15
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Solution
The correct option is
C
30
Series for the required condition:
12
,
16
,
20
,
.
.
.
.96
Two digit positive integers divisible by
4
are
96
=
12
+
(
n
−
1
)
4
⇒
n
=
22
Series for two digits divisible by
9
is
18
,
27
,
.
.
.
.
,
99
Two digit positive integers divisible by
9
99
=
18
+
(
m
−
1
)
9
⇒
m
=
10
Number divisible by both
4
and
9
=
2
i.e.
36
,
72
Total numbers
=
22
+
10
−
2
=
30
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