Byju's Answer
Standard XII
Mathematics
Permutation under Restriction
How many 3-...
Question
How many
3
-digit numbers can be formed by using the digits
1
to
9
if no digit is repeated?
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Solution
A three digit number is to be formed from given
9
digits
1
,
2
,
3
,
4
,
5
,
6
,
7
,
8
,
9
.
□
□
□
H
T
O
⇒
Now, there are
9
ways to fill
O
n
e
s
place.
⇒
Since repetition is not allowed, so
T
e
n
s
place can be filled by the remaining
8
digits.
So, tens place can be filled in
8
ways.
⇒
Similarly, to fill
H
u
n
d
r
e
d
s
of places, we have
7
digits remaining.
So, hundreds can be filled by
7
ways.
⇒
So, the required number of ways in which three-digit numbers can be formed from the given digits is
9
×
8
×
7
=
504
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4
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