How many $3$ digit numbers can be formed using the digits $0, 1, 2, 3, 4, 5, 6, 7, 8$ where digits may be repeated?

900

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980

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800

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250

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Solution

The correct option is C $900$
$0, 1, 2, 3, 4, 5, 6, 7, 8$
Repetition allowed
Number of digits $= 9$
$= 9 \times 9 \times 8 = 81 \times 8$
$= 648$
Note : if the question is $0, 1, 2, 3, 4, 5, 6, 7, 8, 9$
$= 9 \times 9 \times 10$
Then the answer is $900$

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