How many $3$ -digit numbers can be formed with the digits $1, 2, 3, 4, 5$ such that each digit can be used any number of times

5^{3}

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3^{5}

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3^{3}

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5^{5}

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Solution

The correct option is A $5^{3}$
All the $3$ places can be filled with any of the $5$ digits given
So total number of numbers formed $= 5^{3}$

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Similar questions

How many number of four digits can be formed with the digits 1,2,3,4,5 if the digit can be repeated in any number of times?

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