How many $3 m e t e r$ cubes can be cut from a cuboid measuring $18 m \times 12 m \times 9 m$ ?

70

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75

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76

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72

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Solution

The correct option is D $72$
Volume of cuboid $= 18 \times 12 \times 9 = 1944 m^{3}$
Volume of a cube $= 3^{3} = 27 m^{3}$
Therefore,
No. of cubes $= \frac{Volume of cuboid}{Volume of 1 cube} = \frac{1944}{27} = 72 cubes$

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