Question

How many 4-digit numbers can be formed from the digits 1,2,3,5,6 and 8 which are divisible by 5 and none of the digits are repeated?

• A. 20
• B. 40
• C. 60
• D. 80

Answer 1

The correct option is C 60

Since the number should be divisible by 5, last digit has to be 5.
Hence, the number would be of the form __ __ __ 5.
No. of possible numbers, without repetition ${=}^5{C}_1{\times }^4{C}_1{\times }^3{C}_1=60$