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Question
How many 4 digit numbers greater than 5000 can be formed by using the digits 2, 3, 5, 6, 7 and 8 such that digits can get repeated?
How many 4 digit numbers greater than 5000 can be formed by using the digits 2, 3, 5, 6, 7 and 8 such that digits can get repeated?
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Solution
The correct option is C 864
When the repetition is allowed: All the places: Hundred’s, ten’s and unit’s can be filled by any of the digits: 2, 3, 5, 6, 7 or 8 i.e. in 6 ways.
Thousand’s place can be filled only in 4 ways. Hence no. numbers possible = 4×6×6×6 = 864.
When the repetition is allowed: All the places: Hundred’s, ten’s and unit’s can be filled by any of the digits: 2, 3, 5, 6, 7 or 8 i.e. in 6 ways.
Thousand’s place can be filled only in 4 ways. Hence no. numbers possible = 4×6×6×6 = 864.
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