CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

How many 5 digit numbers can be formed from the digits 0, 1, 3, 7, 9 without repetition which are greater than 40000?

A
120
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
96
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
48
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 48
Given digits: 0,1,3,7,9

Since, the number formed has to be greater than 40000

First place can be filled by 2 ways: 7 or 9

Second place be filled by 4 ways: any remaining 4 numbers.

Third place can be filled by 3 ways: any remaining 3 numbers

Fourth place can be filled by 2 ways: any remaining 2 numbers.

Fifth place can be filled by 1 ways: last number remaining


Total number of 5 digits number greater than 40000 =2×4×3×2×1=48



flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Arrangement with Constraints
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon