How many 7-digit numbers are there having the digit 3(three times ) and the digit 0(four times ) ?

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3^{3} \times 4^{4}

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None of these

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Solution

The correct option is A 15

$d_{1}$
is 3 because we have to form 7 digit number now we have rest six boxes
$d_{2}, d_{3}, d_{4}, d_{5}, d_{6}, d_{7}$
to be filled, this can be done in

$\frac{6!}{2! \times 4!} = 15 w a y s$

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