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Standard XII

Chemistry

Nature of Electromagnetic Radiation

How many α ...

Question

How many $α$ and $β$ particles are emitted when $_{92} U^{238}$ disintegrates to form lead $_{82} {P b}^{206}$ ?

6 α, 8 β

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6 α, 6 β

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8 α, 6 β

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4 α, 3 β

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Solution

The correct option is C $8 α, 6 β$

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Similar questions

Q. If by successive disintegration of

{_{92} U}^{238}

, the final product obtained is

{_{82} P b}^{206}

, then how many number of

α

and

β

particles are emitted?

Q. In successive emission of

α

- and

β

- particles, the number of

α

- and

β

- particles that should be emitted for the conversion of

_{92} U^{238}

_{82} {P b}^{206}

are

Q. Number of

α

and

β

particles emitted when uranium nucleus

_{92} U^{238}

decays to

_{82} P b^{214}

are

Q. In the uranium radioactive series, the initial nucleus is

{_{92} U}^{238}

and that the final nucleus is

{_{82} P b}^{206}

. When uranium nucleus decays to lead the number of

α

- particles and

β -

particles emitted are:

A nucleus with Z = 92 emits the following in a sequence: $α, β^{-}, β^{-}, α, α, α, α, α, β^{-}, β^{-}, α, β^{+}, β^{+}, α,$ The Z of the resultant nucleus is

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How many α and β particles are emitted when 92U238 disintegrates to form lead 82Pb206 ?

The correct option is C 8α, 6β

How many $α$ and $β$ particles are emitted when $_{92} U^{238}$ disintegrates to form lead $_{82} {P b}^{206}$ ?

The correct option is C $8 α, 6 β$