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Atomic Number

How many α ...

Question

How many $α$ and $β - p a r t i c l e s$ will be emitted when $_{90} T h^{232}$ changes into $_{82} P b^{208}$ ?

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Solution

Suppose $_{90} T h^{232} \to_{82} P b^{208} + m_{2}^{4} H e + n_{- 1}^{0} e$
Equating mass numbers, $232 = 208 + 4 m$ or $m = 6$
Equating atomic numbers : $90 = 82 + 12 + (- n)$ or $n = 4$
Thus, $6 α$ and $4 β^{-}$ particles will be emitted.

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