How many atom(s) of $S (C H_{2}) F_{4}$ may lie in the equatorial plane ?

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Solution

Four atoms of $S (C H_{2}) F_{4}$ may lie in the equatorial plane. $S (C H_{2}) F_{4}$ has trigonal bipyramidal geometry.The methylene group occupies one of the equatorial position.The rest of the positions are filled by four $F$ atoms.

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