Question

How many atoms are present in 22.4 L of $O_2$ at STP?

• A. $3\times {10}^{23}$
• B. $6\times {10}^{23}$
• C. $9\times {10}^{23}$
• D. $12\times {10}^{23}$
• E. $15\times {10}^{23}$

Answer 1

The correct option is D $12\times {10}^{23}$

Number of moles in 22.4 L of $O_2$ at STP $=$$22.4/22.4$$=$$1mole$

Number of atoms present in 1 mole of oxygen$=$$6\times {10}^{23}$

so total no. of oxygen atoms$=$$2\times 6\times {10}^{23}$$=$$12\times {10}^{23}atoms$