How many atoms are present in the given reaction?

${P b ({N O}_{3})}_{2} + 2 K I \to P b I_{2} + 2 K N O_{3}$

5

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12

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13

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18

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26

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Solution

The correct option is A $26$
The equilibrium reaction is :
${P b ({N O}_{3})}_{2} + 2 K I \to P b I_{2} + 2 K N O_{3}$
${P b ({N O}_{3})}_{2}$ has one $P b$ atom, $2 N$ atoms and $6$ oxygen atoms which is equal to $1 + 2 + 6 = 9$ atoms.
$2 K I$ molecules corresponds to $2 K$ and $2 I$ atoms which totals $4$ atoms.
$P b I_{2}$ has one $P b$ atom and three I atoms that totals $3$ atoms.
$2 K N O_{3}$ has $2 K$ atoms, $2 N$ atoms and $6 O$ atoms that totals $2 + 2 + 6 = 10$ atoms.
Hence, the total number of atoms in the equilibrium is $9 + 4 + 3 + 10 = 26$ atoms.

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Similar questions

Q. Observe the following chemical equation. And answer the questions.

P b (N O_{3})_{2} + 2 K I \to P b I_{2} + 2 K N O_{3}

(i) What are the reactants?
(ii) What are the products?
(iii) Which type of chemical reaction it is?
(iv) What is the colour of

P b I_{2}

Q. Product is solid precipitate for which of the reaction (Assume aqueous reactants)?
i.

A g {N O}_{3} + N a C l \to N a {N O}_{3} + A g C l

ii.

{P b ({N O}_{3})}_{2} + 2 K I \to P b I_{2} + 2 K N O_{3}

iii.

2 N a O H + H_{2} {S O}_{4} \to {N a}_{2} {S O}_{4} + 2 H_{2} O

Given the reaction:-

$P b {(N O_{3})}_{2} (a q) + 2 K I \to P b I_{2} (s) + 2 K N O_{3} (a q)$ What is the mass of $P b I_{2}$ that will precipitate if 10.2 g of $P b {(N O_{3})}_{2}$ is mixed with 5.73 g of $K I$ in a sufficient quantity of $H_{2} O$ ?

Q. Identify the type of reaction(s) in the following equations.
(i)

C H_{4} + 2 O_{2} \to 2 H_{2} O

(ii)

P b (N O_{3})_{2} + 2 K I \to P b I_{2} + 2 K N O_{2}

(iii)

C a O + H_{2} O \to C a (O H)_{2}

(iv) CuSO_4+Zn\rightarrow ZnSO_4+Cu\)

Q. The reaction

P b (N O_{3})_{2} + 2 N a I \to 2 N a N O_{3} + P b I_{2} ↓

is classified as:

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How many atoms are present in the given reaction?

${P b ({N O}_{3})}_{2} + 2 K I \to P b I_{2} + 2 K N O_{3}$