Question

How many atoms do make a piece of aluminium foil which has mass of 27 grams?

• A. $1.20\times {10}^{24}$ atoms
• B. $6.02\times {10}^{23}$ atoms
• C. $3.01\times {10}^{23}$ atoms
• D. 27 atoms
• E. 13 atoms

Answer 1

The correct option is B $6.02\times {10}^{23}$ atoms

The atomic mass of aluminium is $27g$, which means one mole of aluminium contains $27g$ of aluminium.

Now we know that one mole of any element contains $6.02\times {10}^{23}$ atoms.

So, number of atoms in one mole of aluminium $=6.02\times {10}^{23}$or number of atoms in $27g$ of aluminium $=6.02\times {10}^{23}$