How many atoms do mercury vapour molecules consists of, if the density of mercury vapour relative to air is $6.92$ ? ( $H g = 200$ ). The average mass of air is $29 g / m o l$ .

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Solution

At the same temperature and pressure, equal moles of gas have the same volume.
$∴$ Volume of air $=$ Volume of mercury
Now, Mercury vapour is $6.92$ times denser than air.
Also. $1$ $m o l e$ of mercury vapour weights $6.92$ in $1$ $m o l e$ of air.
$1$ $m o l e$ of air $= 29$ $g$
$⟹ 1$ $m o l e$ of mercury vapour $= 6.92 \times 29 = 200.68$ $g$
Now, Mass (atomic) of mercury $= 200$ $g$
So, $1$ atom is present in each mercury molecule.

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How many atoms do mercury vapour molecules consists of, if the density of mercury vapour relative to air is 6.92? (Hg=200). The average mass of air is 29 g/mol.

How many atoms do mercury vapour molecules consists of, if the density of mercury vapour relative to air is $6.92$ ? ( $H g = 200$ ). The average mass of air is $29 g / m o l$ .