The correct option is D 38
During aerobic respiration, complete oxidation of one glucose molecule produces 38 ATP molecules. Aerobic respiration involves glycolysis, link reaction (oxidative decarboxylation of pyruvate), Krebs cycle and oxidative phosphorylation.
During glycolysis, there is net gain of 2 molecules of ATP and also 2 molecules of NADH+H+ are produced.
Oxidation of 1 molecule of NADH+H+ yields 3 molecules of ATP, so, 2 molecules of NADH+H+ yield 6 molecules of ATP. Therefore in glycolysis:
Total ATP produced = 2 ATP + 6 ATP (produced by oxidation of NADH+H+)
= 8 ATP.
Thus glycolysis yields 8 ATP molecules.
Pyruvate formed during glycolysis in the cytoplasm enters mitochondria and undergoes oxidative decarboxylation to form acetyl CoA. During this reaction, one NADH+H+ is produced.
As 2 molecules of pyruvate are formed from one molecule of glucose, 2 molecules of pyruvate undergo oxidative decarboxylation and produce 2 molecules of NADH+H+.
Oxidation of 2 molecules of NADH+H+ yields 6 ATP molecules. Oxidative decarboxylation of pyruvate results in formation of acetyl CoA.
Acetyl CoA enters the Krebs cycle which is a cyclic pathway. In one turn of Krebs cycle, 3 molecules of NADH+H+, 1 molecule of FADH2 and 1 molecule of ATP are produced.
As 2 molecules of acetyl CoA are produced, there are two turns of the Krebs cycle. So, for 2 turns of Krebs cycle, 6 molecules of NADH+H+, 2 molecules of FADH2 and 2 molecules of ATP are produced.
Oxidation of 1 molecule of NADH+H+ yields 3 molecules of ATP.
Oxidation of 1 molecule of FADH2 yields 2 molecules of ATP.
Total ATP produced in Krebs cycle = 18 ATP (oxidation of 6 NADH+H+) + 4 ATP (oxidation of 2 FADH2) + 2ATP
= 24 ATP
Thus, Krebs cycle yields 24 ATP molecules.
Oxidation of NADH+H+ and FADH2 occurs in the inner mitochondrial membrane that has an electron transport chain.
Hence, during the complete oxidation of one molecule of glucose, 38 molecules of ATP are produced.