How many bricks each measuring $(25 c m \times 11.25 c m \times 6 c m)$ will be required to construct a wall $(8 m \times 6 m \times 22.5 c m) ?$

(a) 8000 (b) 6400 (c) 4800 (d) 7200

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Solution

Number of bricks = $fraction numerator v o l u m e space o f space w a l l over denominator v o l u m e space o f space 1 space b r i c k end fraction$

= (800 x 600 x 22.5)× $fraction numerator 1 over denominator 25 cross times 11.25 cross times 6 end fraction$
= 6400

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Similar questions

How many bricks, each measuring 25 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8m x 6m x 22.5 cm?

8 m \times 6 m \times 22.5 c m

25 c m \times 11.25 c m \times 6 c m

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