Question

How many bricks, each measuring $25cm$ $\times$ $11.25cm$ $\times$ $6cm$, Will be needed to build a wall $8m\times 6m\times$ $22.5cm$ ?

Answer 1

R.E.F image

Find the number of bricks

$1m=100cm$

$\to$ for a single bricks, $l\times b\times h=25\times 11.25\times 6$

$\to$ for a wall, $l\times b\times h=8m\times 6m\times 22.5cm$

$\to$ Volume of single brinks $=l\times b\times h$

$=25\times 11.25\times 6$

$=1687.5c{m}^3$

$\to$ Volume of a wall $=l\times b\times h$

$=800\times 600\times 22.5$

$=10,800,000c{m}^3$

$\to$ Volume of u wall $=$ no. of bricks $\times$ volume of

a single bricks

$\therefore 10,800,000=n\times 1687.5$

$\therefore n=\frac{10,800,000}{1687.5}$

$\therefore n=6400$

$\to$ bricks required to construct the wall is

6400.