How many bricks- each measuring 25cm- 12-5cm- 7-5cm will be needed to construct a wall 15m long- 1-8m high and 37-5cm thick-

The correct option is C 4320 Both the brick and the wall are in the shape of a cuboid. Volume nbsp;of a cuboid of length l, breadth b and height h = ...

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Standard IX

Mathematics

Volume of a cuboid

How many bric...

Question

How many bricks, each measuring $25 c m \times 12.5 c m \times 7.5 c m$ will be needed to construct a wall $15 m$ long, $1.8 m$ high and $37.5 c m$ thick?

4400

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4660

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4320

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4575

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Solution

The correct option is C $4320$
Both the brick and the wall are in the shape of a cuboid.
Volume of a cuboid of length l, breadth b and height h $= l \times b \times h$ .
Considering all the measures in cm, number of bricks required $= \frac{V o l u m e o f t h e w a l l}{V o l u m e o f o n e b r i c k} = \frac{1500 \times 180 \times 37.50}{25 \times 12.5 \times 7.5} = 4320$

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Q. How many bricks will be required to construct a wall 8 m long, 6 m high and 22.5 cm thick if each brick measures (25 cm × 11.25 cm × 6 cm)?

Q. How many bricks will be required to construct a wall 8 m long, 6 m high and 22.5 cm thick if each brick measures (25 cm × 11.25 cm × 6 cm)?
(a) 4800
(b) 5600
(c) 6400
(d) 5200

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(b) 6000

(d) 7200

Find the number of bricks, each measuring 25 cm long, 12.5 cm high and 7.5 cm thick required to construct a wall 6 m long, 5 m high and 0.5 m thick, while the cement and sand mixture occupies ignored.

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How many bricks, each measuring 25cm×12.5cm×7.5cm will be needed to construct a wall 15m long, 1.8m high and 37.5cm thick?

The correct option is C 4320Both the brick and the wall are in the shape of a cuboid. Volume of a cuboid of length l, breadth b and height h =l×b×h.Considering all the measures in cm, number of bricks required =VolumeofthewallVolumeofonebrick=1500×180×37.5025×12.5×7.5=4320

How many bricks, each measuring $25 c m \times 12.5 c m \times 7.5 c m$ will be needed to construct a wall $15 m$ long, $1.8 m$ high and $37.5 c m$ thick?