How many bricks of size 25 cm 15 cm 6 cm are required to make a wall 5 cm long , 2 m high and 50 cm thick , if 10% place is occupied by cement ?

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Solution

Volume of brick = $25 \times 15 \times 6 = 2250$ $c m^{3}$
Volume of wall = $5 \times 200 \times 50 = 50000$ $c m^{3}$
10 % of volume of wall is occupied by cement, therefore, volume of wall left for bricks is :
$= 50000 - \frac{10}{100} \times 50000 = 50000 - 5000 = 45000$ $c m^{3}$
Hence,
Number of bricks required = $\frac{45000}{2250} = 20$

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Question 117

Q. A wall

24

m long,

5

m high and

0.25

m thick is to be constructed using bricks measuring

25

\times 12.5

\times 7.5

cm. Find the number of bricks required, if

5 %

of the wall is occupied by cement and sand mixture.

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How many bricks of size 25 cm 15 cm 6 cm are required to make a wall 5 cm long , 2 m high and 50 cm thick , if 10% place is occupied by cement ?

Volume of brick = 25×15×6=2250 cm3Volume of wall = 5×200×50=50000 cm310 % of volume of wall is occupied by cement, therefore, volume of wall left for bricks is :=50000−10100×50000=50000−5000=45000 cm3Hence,Number of bricks required = 450002250=20