Question

How many bricks will be required to construct a wall $8m$ long, $6m$ high and $22.5cm$ thick if each brick measures $(25cm\times 11.25cm\times 6cm)$?

Answer 1

The dimension of the wall are
Length $=8m=800cm$
Breadth $=6m=600cm$
Height $=22.5cm$

We know that

Volume of the wall$=1\times b\times h$

By substituting the values

Volume of the wall $=800\times 600\times 22.5$

By multiplication

Volume of the wall $=10800000c{m}^3$

The dimension of the brick are

Length $=25cm$

Breadth $=11.25cm$

Height $=5cm$

We know that

Volume of one brick $=1\times b\times h$

By substituting the values

Volume of one brick $=25\times 11.25\times 6$

By multiplication

Volume of one brick $=1687.5c{m}^3$

So the number of brick required $=\frac{Volumeofwall}{Volumeofbrick}$

By substituting the values

Number of brick required $=\frac{10800000}{1687.5}$

By division

Number of brick requited $=6400$

Therefore, the number of bricks required to construct a wall is $6400$.