How many calories of heat are required by gram of water at $99^{o} C$ to boil off:

530

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640

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540

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500

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Solution

The correct option is B 540
Heat $= 4.2 (1) (1) + 1 (2260) = 2264.2 J$
$1 c a l = 4.2 J$
Thus, Heat $= 539.1 c a l \approx 540 c a l$

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One calorie is the heat energy required to raise the temperature of one gram of water by ___ degree Celsius at a pressure of one atmosphere.

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