Question

How many candidates were interviewed everyday by the panel A out of the three panels A, B and C?
I. The three panels on average interview $15$ candidates every day.
II. Out of a total of $45$ candidates interviewed everyday by the three panels, the number of candidates interviewed by panel A is more by $2$ than the candidates interviewed by panel c and is more by $1$ than the candidates interviewed by panel B.

• A. I alone sufficient while II alone not sufficient to answer
• B. II alone sufficient while alone not sufficient to answer
• C. Either I or II alone sufficient to answer
• D. Both I and II are not sufficient to answer
• E. Both I and II are necessary to answer

Answer 1

Answer: (B)

II alone sufficient while alone not sufficient to answer

I. Total candidates interviewed by $3$ panels $=(15\times 3)=45$.
II. Let x candidates be interviewed by C.
Number of candidates interviewed by $A=(x+2)$.
Number of candidates interviewed by $B=(x+1)$.
$\therefore x+(x+2)+(x+1)=45$
$\Rightarrow 3x=42$
$\Rightarrow x=14$
Hence, the correct answer is (B).