How many carbon atoms are present in 0-35 mol of C-6H-12O-6-1-26 - 10-24 carbon atoms-6-023 - 10-24 carbon atoms-6-023 - 10-23 carbon atoms-1-26 - 10-23 carbon atoms-

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Mole Concept and Avogadro's Number

How many carb...

Question

How many carbon atoms are present in 0.35 mol of $C_{6} H_{12} O_{6}$ :

$6.023 \times 10^{23}$ carbon atoms

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$1.26 \times 10^{23}$ carbon atoms

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$1.26 \times 10^{24}$ carbon atoms

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$6.023 \times 10^{24}$ carbon atoms

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Solution

The correct option is B
$1.26 \times 10^{23}$ carbon atoms

$∴$ 1 mol of $C_{6} H_{12} O_{6}$ has = 6 $N_{A}$ atoms of C $∴$ 0.35 mol of $C_{6} H_{12} O_{6}$ = $6 \times 0.35$ $N_{A}$ atoms of C = 2.1 $N_{A}$ atoms
= $2.1 \times 6.022 \times 10^{23} = 1.26 \times 10^{24}$ carbon atoms

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Q. How many carbon atoms are present in 0.35 mol of

C_{6} H_{12} O_{6}

Q. How many carbon atoms are present in 0.35 mol of

C_{6} H_{12} O_{6}

Q. How many carbon atoms are present in 0.35 mol of

C_{6} H_{12} O_{6}

Q. A graphite pencil weighs

3.0 \times 10^{- 10} g .

How many carbon atoms are present in it?

(N_{A} = 6 \times 10^{23})

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How many carbon atoms are present in 0.35 mol of C6H12O6:

The correct option is B 1.26×1023 carbon atoms ∴ 1 mol of C6H12O6 has = 6 NA atoms of C ∴ 0.35 mol of C6H12O6 = 6×0.35 NA atoms of C = 2.1 NA atoms = 2.1×6.022×1023=1.26×1024 carbon atoms

How many carbon atoms are present in 0.35 mol of $C_{6} H_{12} O_{6}$ :

The correct option is B
$1.26 \times 10^{23}$ carbon atoms

$∴$ 1 mol of $C_{6} H_{12} O_{6}$ has = 6 $N_{A}$ atoms of C $∴$ 0.35 mol of $C_{6} H_{12} O_{6}$ = $6 \times 0.35$ $N_{A}$ atoms of C = 2.1 $N_{A}$ atoms
= $2.1 \times 6.022 \times 10^{23} = 1.26 \times 10^{24}$ carbon atoms