Question

How many carbon atoms are present in 0.35 mol of $C_6{H}_{12}{O}_6$ :

• A. carbon atoms
• B. carbon atoms
• C. carbon atoms
• D. carbon atoms

Answer 1

The correct option is B carbon atoms

$\therefore$ 1 mole of $C_6{H}_{12}{O}_6$ has $=6N_A$ atoms of C

$\therefore$ 0.35 mole of $C_6{H}_{1}2O_6$ has $=6\times 0.35N_A$ atoms of $C=2.1N_A$ atoms
$=2.1\times 6.022\times {10}^{23}=1.26\times {10}^{24}$ carbon atoms