How many carbon atoms are there in the simplest alkane capable of exhibiting chain isomerism?

three

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five

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four

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six

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Solution

The correct option is C four
$C H_{4}$ has no chain isomer.

$C_{2} H_{6}$ has no chain isomer.

$C_{3} H_{8}$ has no chain isomer.

$C_{4} H_{10}$ has 2 chain isomers.

Therefore, 4 carbon atoms.

Option C is correct.

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