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Question
How many chain isomers are possible for C6H14?
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Solution
The correct option is B 3
CH3−CH2−CH2−CH2−CH2−CH3−(i)
CH3−CH2−CH−CH2−CH3(ii) |CH3
CH3| CH3|CH3−CH−CH−CH3−(iii)
CH3−CH2−CH2−CH2−CH2−CH3−(i)
CH3−CH2−CH−CH2−CH3(ii) |CH3
CH3| CH3|CH3−CH−CH−CH3−(iii)
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