Question

How many $Cl$ atoms can you ionize in the process $Cl\to {Cl}^{+}+e$ by the energy liberated for the process $Cl+e\to {Cl}^{-}$ for one Avogadro number of atms. Given $IP=13.0eV$ and $EA=3.60eV$. Avogadro number $=6\times {10}^{23}$.

Answer 1

Ionization potential is the energy required to remove an electron from the outermost shell of an atom.

$\therefore Cl⟶C{l}^{+}+e^{-}$ ; $E=13.0$ $eV$

Electron affinity is the property of an atom to attract an electron.

$\therefore Cl+e^{-}⟶Cl$ ;$E=-3.6$ $eV$

$\therefore$ Moles of Cl atoms that can be ionized= $\frac{3.6eV}{13.0eV}=0.277$ moles

No. of atoms= $0.277\times 6.022\times {10}^{23}$

=$1.667\times {10}^{23}$ atoms