How many combinations are possible if $3$ one rupee coin, $4$ fifty paise coin and $2$ twenty five paise coin are available. It is compulsory to select any one of the coin.

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Solution

For every coin you can either select it or not
So, $(3 + 1) \times (4 + 1) \times (2 + 1) - 1 = 59$
$1$ is subtracted because we have considered the case where no coin is selected.

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How many combinations are possible if 3 one rupee coin, 4 fifty paise coin and 2 twenty five paise coin are available. It is compulsory to select any one of the coin.

For every coin you can either select it or notSo, (3+1)×(4+1)×(2+1)−1=591 is subtracted because we have considered the case where no coin is selected.

How many combinations are possible if $3$ one rupee coin, $4$ fifty paise coin and $2$ twenty five paise coin are available. It is compulsory to select any one of the coin.

For every coin you can either select it or not
So, $(3 + 1) \times (4 + 1) \times (2 + 1) - 1 = 59$
$1$ is subtracted because we have considered the case where no coin is selected.