How many compounds liberate $N H_{3}$ on heating from the following?
$(N H_{4})_{2} S O_{4}$ , $(N H_{4})_{2} C O_{3}$ , $N H_{4} C l$ , $N H_{4} N O_{3}$ , $(N H_{4})_{2} C r_{2} O_{7}$

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Solution

Three compounds $(N H_{4})_{2} C O_{3}$ , $N H_{4} C l$ and $(N H_{4})_{2} S O_{4}$ , liberate $N H_{3}$ on heating.
$(N H_{4})_{2} C O_{3} h e a t - - \to 2 N H_{3} + H_{2} O + C O_{2}$
$N H_{4} C l h e a t - - \to N H_{3} + H C l$
$(N H_{4})_{2} S O_{4}$ cannot be used for the preparation of ammonia as ammonia reacts with sulphuric acid (dehydrating agent).
$2 N H_{3} + H_{2} S O_{4} \to (N H_{4})_{2} S O_{4}$
$(N H_{4})_{2} C r_{2} O_{7}$ on heating liberates nitrogen.
$(N H_{4})_{2} C r_{2} O_{7} h e a t - - \to N_{2} + C r_{2} O_{3} (Green) + 4 H_{2} O$
$N H_{4} N O_{3}$ on heating forms ammonium nitrate.
$N H_{4} N O_{3} h e a t - - \to N_{2} O + 2 H_{2} O$

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