How many consecutive odd numbers will be needed to obtain the sum of $4^{3}$ ?

2

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3

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4

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5

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Solution

The correct option is A $4$
We know,
$1 = 1 = 1^{3}$ ,
$3 + 5 = 8 = 2^{3}$ ,
$7 + 9 + 11 = 27 = 3^{3}$ ,
$13 + 15 + 17 + 19 = 64 = 4^{3}$ .

$∴$ $4$ consecutive odd numbers are required to obtain the sum as $4^{3}$ .
Hence, option $C$ is correct.

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