Question

How many coulombs are required for the oxidation of 1 mol of $H_2{O}_2$ to $O_2?$

• A. 9.65 × 10⁴ C
• B. 93000 C
• C. 1.93 × 10⁵ C
• D. 19.3 × 10² C

Answer 1

The correct option is C 1.93 × 10⁵ C

$H_2{O}_2⟶O_2+2H^{+}+2e^{-}$
$1mol{H}_2{O}_2\equiv 2mole{e}^{-}$
$\equiv 2\times 96500C\equiv 193000C$
$=1.93\times {10}^{-}5C$