Question

How many coulombs are required for the oxidation of 1 mol of $H_{2}Oto{O}_2$?

• A. $93000C$
• B. $1.93\times {10}^{5}C$
• C. $9.65\times {10}^{4}C$
• D. $19.3\times {10}^{2}C$

Answer 1

The correct option is B $1.93\times {10}^{5}C$

$H_{2}O\to 2H^{\oplus }+2e^{-}+\frac{1}{2}{O}_2$

$2F\equiv 1molof{H}_{2}O=\frac{1}{2}molof{O}_2$

$\therefore 2\times 96500C=1.93\times {10}^{5}C$

Hence, option B is correct.