Question

How many coulombs must be applied to a cell for the electrolytic production of $245gNaCl{O}_4$ from $NaCl{O}_4$ from $NaCl{O}_3$. The anode efficiency for the desired reaction is $60$%.

Answer 1

$NaCl{O}_3+H_{2}O\to NaCl{O}_4+H_2$

$Cl{O}_3^{-}+H_{2}O\to NaCl{O}_4^{-}+2e{}^{-}+2H{}^{+}$

$n_f=2$

$w=Zit$

$245g=\frac{mol.wt}{n_f\times F}\times Q\times anodeefficiency$

$\frac{245\times 2\times 96500}{122.44\times 0.66}=Q$

$Q=6.669F$