Question

How many coulombs of electricity are required for the oxidation of one mole of water to dioxygen?

• A. $9.65\times {10}^{4}C$
• B. $1.93\times {10}^{4}C$
• C. $1.93\times {10}^{5}C$
• D. $19.3\times {10}^{5}C$

Answer 1

The correct option is C $1.93\times {10}^{5}C$

$H_{2}O\to \frac{1}{2}{O}_2$ or $H_{2}O⟶2H^{+}+O+2e^{-}$

$n_f$ for $O=2$

Therefore 2 moles of electricity is required for oxidation of 1 mol of water.

Hence, charge required $=2\times 96500C=1.93\times {10}^{5}C$