Question

How many coulombs of electricity is required to convert $Al$ to $A{l}^{3+}$?

Answer 1

$A{l}^{+3}+3e^{-}⟶Al$

To convert $1$ $mole$ of $A{l}^{3+}$ $3F$ of electricity is required.

$\therefore 3\times 96500=289500$ $C$