Question

How many cubes of side 3 cm are required to build a cube of side 15 cm?

Answer 1

The side of the small cube$=3cm$

side of the big cube$=15cm$

number of small cubes required$=n$

$n=\frac{\left(volumeofbigcube\right)}{\left(volumeofsmallcube\right)}$

$=\frac{(15cm{)}^3}{(3cm{)}^3}$

$=\frac{15\times 15\times 15}{3\times 3\times 3}$

$=5\times 5\times 5$

$=125$