How many cubes of side length 3 can be fit in a cuboid of dimension $3 \times 6 \times 9$ ?

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Solution

The correct option is B
6

Volume of cuboid $= 3 \times 6 \times 9 = 162$ cubic units

Volume of cube $= 3 \times 3 \times 3 = 27$ cubic units

Number of cubes that can be fit in the cuboid is $\frac{162}{27} = 6$

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