Question

How many cubical boxes of side 9 cm can be accommodated in a cuboidal box of dimensions 18 cm x 27 cm x 9 cm ?

• A. 5
• B. 4
• C. 6
• D. 3

Answer 1

The correct option is C 6

Volume of cubical box
$=9\times 9\times 9=729cucm$
Volume of carton
$=18\times 27\times 9=4,374cucm$

$\text{No. of boxes}=\frac{Volumeofcuboidalbox}{Volumeofeachcubicalbox}$

$\text{No. of boxes}=4374÷$ 729

$\text{No. of boxes}=6$

Let's see this using repeated subtraction

4374 - 729 = 3645
3645 - 729 = 2916
2916 - 729 = 2187
2187 - 729 = 1458
1458 - 729 = 729
729 - 729 = 0

After repeated subtraction of 729 from 4374 for 6 times, we will get 0.

So, 4374 $÷$ 729 = 6