How many 'd' electrons are present in $C r^{2 +} i o n$ ?

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Solution

The correct option is A 4
Cr atomic number is 24 (contains 24 electrons) Cr+2 means 2 electrons are lost so totally 22 electrons are there Hence the configaration is 1s2 2s2 2p6 3s2 3p6 3d4,so d orbital contains 4 electrons

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