How many d-orbital(s) is/are involved in hybridization of $[A u C l_{4}]^{-}$ ?

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Solution

The correct option is D 1
Option (D) is correct.
Tetrachloroaurate $[A u C l_{4}]^{-}$ is $d s p^{2}$ (or $s p^{2} d$ ) hybridized. One 4s, two 4p orbitals (on the x and y axes), and one 3d orbital from the Au(III) become hybridized. There are no unpaired electrons in this polyatomic ion.
This hybridization is usually not discussed much in general chemistry.

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