Question

How many days are present from year 2005 to 2008 including these years?

Answer 1

1 year $=$ 365 days.
From 2005 to 2008 $=$ 4 years and 2008 is a leap year i.e., 366 days.
$\therefore$ No. of days from year 2005 to 2008 $=(365\times 4)+1=1461days$